Question

(1 point) Given the system of inequalities below, determine the shape of the feasible region andfind the vertices of the feasible region. Give the shape as "triangle", "quadrilateral", or"unbounded". Report your vertices starting with the one which has the smallest x-value. If morethan one vertex has the same, smallest x-value, start with the one that has the smallest y-value.Proceed clockwise from the first vertex. Leave any unnecessary answer spaces blank.x + y < 23x + y 23x + 4y <3x > 0y > 0The shape of the feasible region is quadrilateralThe first vertex is).The second vertex is ().The third vertex is).The fourth vertex is ().

Answer 1

First, let's graph all the inequalities.

As you can observe in the image above, the region formed by the given system is a triangle, in which vertices are

• (0.818, 0.545)

,

• (1.667, 0.333)

,

• (0.5, 1.5)