Question

Divide the binomial by the monomial to find the quotient -36x^4y + 144x^2 y^6/ -4x^2y

Answer 1

The way that you would do this is by taking
`-4x^(2)` out of the binomial, or as I like to think about it, 'un-distributing'. :p

`-4x^(2)` out of
`-36x^(2)y`, you end up with
`12x^(2)`.
When you take
`-4x^(2)` out of
`144x^(2)y{6}`, you get
`-36y^(5)`.
Put it together, and the solution is
`12x^(2)` -
`36y^(5)`.

Hope I helped!!

Answer 2

The quotient is:

`9x^2-36y^5`

Explanation:

We are asked to find the quotient when a binomial is divided by the monomial.

The expression is as follows:

`(-36x^4y+144x^2y^6)/(-4x^2y)`

on taking out the common factors from the numerator term of the expression we get:

`-36x^4y+144x^2y^6=36x^2y(-x^2+4y^5)`

Hence, we get:

`(-36x^4y+144x^2y^6)/(-4x^2y)=(36x^2y(-x^2+4y^5))/(-4x^2y)\\\\\\(-36x^4y+144x^2y^6)/(-4x^2y)=-9(-x^2+4y^5)\\\\\\i.e.\\\\\\(-36x^4y+144x^2y^6)/(-4x^2y)=9(x^2-4y^5)`

Hence, the quotient is:

`9x^2-36y^5`