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Chris's uncle has a model car. The model is 6 inches long and 3 inches wide. The actual car is 75 inches long. What is the cars actual width, if we assume the models proportions are accurate? If necessary, round to the nearest tenth of an inch. A. 25 inches B. 37.5 inches C. 150 inches D. 225 inches

2 Answers

6 votes

Answer:

Option B is correct.

The actual width of the car model is, 37.5 inches.

Explanation:

It is given that Chris's uncle has a model car and the length of model is 6 inches long and 3 inches wide. The actual car is 75 inches long.

Proportions is simply a statement that the two ratios are equal.

It can be written in two ways i.e,


(a)/(b) =(c)/(d) or


a: b = c : d

Since; length of the car model = 6 inches , width = 3 inches and the actual length of car is 75 inches;

Let the actual width be x

By using definition of proportion;


6 : 3 = 75 : x or


(6)/(3) =(75)/(x)

Simplify:


2 = (75)/(x)

Multiply both sides by x we get;


2 * x = (75)/(x) * x

Simplify:


2x = 75

Divide by 2 to both sides of an equation we get;


(2x)/(2) =(75)/(2)

Simplify:

x =37.5 inches.

Therefore, the actual width of the car is; 37.5 inches.



User Nitish Pareek
by
6.6k points
3 votes

The model car has a length to width ratio of 6 : 3 therefore the actual car should also have similar ratio. Let us say that x is the width of the actual car, hence:

6 : 3 = 75 : x

6 / 3 = 75 / x

Calculating for x:

x = 75 * 3 / 6

x = 37.5 inches

Answer: B

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