Question

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Answer 1

Alright, so I'll give you some general guidelines and challenge you to solve this on your own!

If we have a number x , a number z, and a number y, then

`x^{y^(z)} = x^(y * z)`
For example,

`2^{3^(4)} = 2^(3*4)=2^(12)`

Next,
`x^(y) * x^(z)=x^(y+z)` . For example,
`2^(3)*2^(4)=2^(3+4)=2^(7)`

Lastly,
`(x^(y))/(x^(z)) =x^(y-z)` . For example,
`(2^(3))/(2^(4)) =2^(3-4)=2^(-1)` . In this situation, note that a negative exponent means we have 1 over the actual positive exponent. For example,
`2^(-1)= (1)/(2^(1)) =1/2`

Please remember PEMDAS as well -
P - Parenthesis
E- Exponents
M/D - Multiplication/Division
A/S - Addition/Subtraction
Go from top to bottom


Good luck, and feel free to ask any questions!