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Need help with linear approximation

Use linear approximation to estimate the following quantities. Choose a value of a to produce a small error.
1/203

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Consider a function f(x), the linear approximation L(x) of f(x) is given by


L(x)=f(a)+(x-a)f'(a)

Given the quantity:
(1)/(203)

We approximate the quantity using the function
f(x)= (1)/(x), where x = 203.

We choose a = 200, thus the linear approximation is given as follows:


L(203)=f(200)+(203-200)f'(200) \\ \\ = (1)/(200) - (3)/(200^2) = (200-3)/(200^2) = (197)/(40,000) =0.004925
User Gregory Demin
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