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Find two consecutive even positive integers whose product is 624

User Magdala
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x(x+2) =624x^2 +2x =624  distribute the x to both factors in the parenthesesx^2 +2x -624=624-624. Move all parts to one side of the equationx^2 +2x -624=0. Simplify, now factor because it is a squared equation(x-24)(x+26)=0 two numbers that equal 624when multiplied but 2 when added together x-24=0. And x+26=0.  Set each factor equal to zero and solvex=24.       And x=-26. Simplifyx+2=26.   and x+2=-24. Finding the second even integerBut wait, the problem wants POSITIVE even integers so 2 of the solutions DO NOT work (-26,-24, they are negative) be careful sometimes you get extraneous ("extra") solutions, look at your defined variables.the solutions we want are 24 and 26. 
User ThriceGood
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