Solution: A rhombus abcd whose area is 72 square units.
Diagonals ac and bd intersect each other at point e.
Also, db= x-1,
ec = 8 units, so, ac=16 units → as diagonals of rhombus bisect each other.
→Area of Rhombus = 1/2 × Product of Diagonals
→ 72 = 1/2×16×(x-1)
→144= 16 (x-1)
Dividing both sides by 16,we get
→ x-1=9
→ x=9+1
→ x=10 units