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The coordinates of the vertices of quadrilateral ABCD are A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2) . Which statement correctly describes whether quadrilateral ABCD is a rhombus?

A. Quadrilateral ABCD is not a rhombus because opposite sides are parallel but the four sides do not all have the same length.
B. Quadrilateral ABCD is a rhombus because opposite sides are parallel and all four sides have the same length.
C. Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.
D. Quadrilateral ABCD is not a rhombus because there is only one pair of opposite sides that are parallel.

25 points for the answer

User Jambo
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2 Answers

4 votes

Answer:

The answer is c.

Step-by-step explanation:

I took this test and got 100%, hope this helps!

User Chris Noe
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5 votes

Answer:

Option C is correct.

Step-by-step explanation:

Rhombus states that a parallelogram with four equal sides and sometimes one with no right angle.

Given: The coordinate of the vertices of quadrilateral ABCD are A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2) .

The condition for the segment
(x_(1),y_(1)),
(x_(2),y_(2)) to be parallel to
(x_(3),y_(3)),
(x_(4),y_(4)) is matching slopes;


(y_(2)-y_(1))/(x_(2)-x_(1))= (y_(4)-y_(3))/(x_(4)-x_(3)) or


(y_(2)-y_(1)) \cdot (x_(4)-x_(3)) =(y_(4)-y_(3)) \cdot (x_(2)-x_(1)) ....[1]

So, we have to check that
AB || CD and
AD || BC

First check
AB || CD

A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2)

substitute in [1],


(5-3) \cdot (-2-3) = (-2-1) \cdot (-1-(-6))


2 \cdot -5 = -3 \cdot 5

-10 ≠ -15

Similarly,

check
AD || BC

A(−6, 3) , D(−2, −2) , B(−1, 5) and C(3, 1)

Substitute in [1], we have


(-2-3) \cdot (3-(-1)) = (1-5) \cdot (-2-(-6))


-5 \cdot 4 = -4 \cdot 4

-20 ≠ -16.

Both pairs of sides are not parallel,

therefore, Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.



User ChrisBarthol
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