Question

Saline solutions (nacl in water) used to deliver intravenous drugs are 0.89%(w/v). what mass of nacl is found in 200 ml of such a solution?

Answer 1

The mass of NaCl found in 200 ml of a 0.89% (w/v) saline solution is 1.78 grams.

Step-by-step explanation:

The concentration of the saline solution is given as 0.89% (w/v), which means that 0.89 grams of NaCl are present in 100 milliliters (ml) of the solution. To calculate the mass of NaCl in 200 ml of the solution, you can use a proportion:

0.89 grams of NaCl / 100 ml = x grams of NaCl / 200 ml

Cross-multiplying and solving for x, we find:

x = (0.89 grams of NaCl / 100 ml) * 200 ml = 1.78 grams of NaCl

Answer 2

A ratio of 0.89% w / v or 0.0089 in fraction means that there is 0.89 weight of NaCl pero volume of solution. Therefore the mass of NaCl is:

mass NaCl = 0.0089 * 200

mass NaCl = 1.78 grams