Two fair, six-sided number cubes are rolled. What is the probability that the sum of the values shown is less than 4? 2/3 1/12 1/4 1/3

Question

asked Sep 12, 2018 13.3k views

2 Answers

AbIr Chanda · Answer 1 · 2018-09-17T23:40:10+0000

Answer:

(1)/(12)

Explanation:

Let S be the sample space, when two fair six-sided number cubes are rolled.

The sample space is in attached pic.

Let E be the event when sum of the values is less than 4.

$E=\left \{ (1,1), (1,2), (2,1) \right \}$

We know that
P(E)=(n(E))/(n(S)) i.e
$P(E)=(number\:of\:elements\:in\:E)/(number\:of\:elements\:in\:S)$

So,
P(E)=(3)/(36)=(1)/(12)