Question

Two fair, six-sided number cubes are rolled. What is the probability that the sum of the values shown is less than 4?

2/3
1/12
1/4
1/3

Answer 1

i believe it is 2/3 not sure but i think so :)

Answer 2

`(1)/(12)`

Explanation:

Let S be the sample space, when two fair six-sided number cubes are rolled.

The sample space is in attached pic.

Let E be the event when sum of the values is less than 4.

`E=\left \{ (1,1), (1,2), (2,1) \right \}`

We know that
`P(E)=(n(E))/(n(S))` i.e
`P(E)=(number\:of\:elements\:in\:E)/(number\:of\:elements\:in\:S)`

So,
`P(E)=(3)/(36)=(1)/(12)`