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What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ? Enter your answer in the box
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Apr 12, 2018
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What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ? Enter your answer in the box
Mathematics
high-school
Archit Baweja
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Archit Baweja
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After adding everything together you should get y=-2x+10
Sooyeon
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Apr 15, 2018
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Sooyeon
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Perpendicular lines' slopes are reciprocals of one another. So we know the perpendicular line will have a slope of 1/2. Then we can use our points to find the rest. 8=1/2(1)+b 8=0.5+b 7.5=b y=2x+b
AYESIGYE DERRICK
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Apr 17, 2018
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AYESIGYE DERRICK
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