Question

One triangle has a height of 15 feet and a base length of 8 feet. It is proportional to a second triangle that has a height of 375 feet. What is the length of the second triangle's base (Hint: draw a visual and set up a proportion)O A 20OB. 28OC 30O 0.70

Answer 1

Using the data from the question, we draw the following triangles:

The dimensions are in feet.

Now, the two triangles are proportional, so if we compute the ratio between the height and the basis of the first triangle, and then we do the same with the second, we must obtain the same number:

`r=(h_1)/(b_1)=(h_2)/(b_2)`

Replacing the dimensions of the triangles in the last equation, we get:

`\begin{gathered} (h_1)/(b_1)=(h_2)/(b_2) \\ (15)/(8)=(375)/(b_2) \end{gathered}`

From the last equation we can compute b2, the basis of the second triangle, doing that we find that:

`\begin{gathered} (15)/(8)=(375)/(b_2) \\ 15\cdot b_2=375\cdot8 \\ b_2=(375\cdot8)/(15) \\ b_2=200 \end{gathered}`

So the second triangle's base is:

`b_2=200`

(in feet)

Answer

A. 200