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Use the quadratic formula to solve for x4x2 +9x=1

User RupertP
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1 Answer

20 votes
20 votes

Answer:

0.10625 and -2.35625

Step-by-step explanation:

Given the equation;

4x^2+9x = 1

4x^2 + 9x - 1 = 0

From the equation a = 4, b = 9 and c = -1

Substitute into the formula;


\begin{gathered} x\text{ = }\frac{-b\pm\sqrt[\square]{b^2-4ac}}{2a} \\ x\text{ = }\frac{-9\pm\sqrt[\square]{81-4(4)(-1)}}{2(4)} \\ x\text{ =}\frac{-9\pm\sqrt[\square]{81+16}}{8} \\ x\text{ }\frac{-9\pm\sqrt[\square]{97}}{8} \\ x\text{ = }(-9\pm9.85)/(8) \\ x\text{ = }(-9+9.85)/(8)\text{ and }(-9-9.85)/(8) \\ x\text{ = 0.85/8 and -18.85/8} \\ x\text{ = }0.10625\text{ and -}2.35625 \end{gathered}

Hence the value of x are 0.10625 and -2.35625

User Veben
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