Question

If f(x)=-5x+1 and g(x)=x^3 what is (g°f)(0)?

Answer 1

`\bf \begin{cases} f(x)=-5x+1\\ g(x)=x^3\\ (g\circ f)(x)=g(~~f(x)~~) \end{cases} \\\\\\ f(0)=-5(0)+1\implies \boxed{f(0)=1} \\\\\\ g(~~f(x)~~)\implies g(~~f(0)~~)\implies g\left( ~~\boxed{1}~~ \right)=(1)^3\implies g(1)=1`