Answer:
y = ax² - (3a + 3)x + 9
Explanation:
The curve passes through 2 points: (3, 0) and (0, 9)
f(3) = 9a + 3b + c = 0
f(0) = 0 + 0 + c = 9
Therefore, c = 9, so plug this into the first equation:
9a + 3b + 9 = 0
We cannot determine a or b but for a given a we find that
b = - 3a - 3 ⇒ -b = 3a + 3
Therefore, we can express the quadratic curve as:
y = ax² - (3a + 3)x + 9