Question

What is the range for the following function? V x + 3 1 + 2 +3 A. {»:YER, 23) O B. (y:YER,y+2) OC. {Y:YER,y+-2) OD. {Y:YER) SUBMIT PREVIOUS

Answer 1

Given the function;

`y=(1)/(x+3)+2`

First, we find the inverse of the function as;

Then, we get the domain of the inverse function, we have;

`x<2\text{ or x>2}`

Thus, the graph of the function is;

Hence, the range of the function is;

`\mleft\lbrace y\colon y\in\mathfrak{\Re },y\\e2\mright\rbrace`

CORRECT OPTION: B