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What is the remainder when the polynomial 8x^2+4x−3 is divided by 2x−1?

User Provisota
by
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2 Answers

4 votes
The remainder of this polynomial is 1. 
User Sheetal Shelar
by
7.1k points
3 votes

Answer:

1

Explanation:

Given: A polynomial
8x^(2) +4x-3 is divided by another polynomial
2x-1

To find: Remainder when
8x^(2) +4x-3 is divided by
2x-1

Solution:

To find the remainder when
8x^(2) +4x-3 is divided by
2x-1

First, equate
2x-1 with 0.

Now,
2x-1=0


\implies2x=1


\implies x=(1)/(2)

Now, to find the remainder put
x=(1)/(2) in
8x^(2) +4x-3

So, we have


8*((1)/(2))^(2)+4((1)/(2) )-3


=8*(1)/(4) +2-3


=2+2-3


=4-3


=1

Hence, the remainder is 1.

User PtQa
by
9.4k points

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