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Please help. Got bad connection and lost my last tutor

Please help. Got bad connection and lost my last tutor-example-1
User Brianstewey
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1 Answer

18 votes
18 votes

To transform the magnitudes, we have to use the given ratios.

So, 1.00 fluid ounces is equivalent to 23.573mL. Now, let's find the volume of a kilogram of water using the density formula


\begin{gathered} \rho=(m)/(V) \\ 1g/cm^3=(1000g)/(V) \\ V=(1000g)/(1g/cm^3) \\ V=1000(cm)^3 \end{gathered}

Once we have the volume of a kilogram of water, we transform it into mL using the given ratio.


V=1000(cm)^3\cdot(1L)/(1000(cm)^3)\cdot(1000mL)/(1L)=1000mL

Once we have the volume in mL, we can find the fluid ounce of 1000mL. Let's use a rule of three


\begin{gathered} (1oz)/(29.573mL)=(x)/(1000mL) \\ x=(1000mL)/(29.573mL)oz \\ x=33.8oz \end{gathered}

Therefore, the number of fluid ounces in a kilogram of water is 33.8 ounces.

User Shubham R
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