Given f(x)=x^2-x; find f(-5)

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asked May 7, 2018 27.7k views

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Abelardo · Answer 1 · 2018-05-12T08:30:49+0000

Plug in - 5 where X is.

f(- 5) = (- 5)^2 - ( - 5).

(- 5)( - 5) = 25 so now we have 25 - (- 5). Because there are two negatives back to back, the number becomes a positive so the equation becomes 25 + 5 = 30.

f(- 5) = 30.

Given f(x)=x^2-x; find f(-5)

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