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A sample of propane (C3H8) has a mass of 0.47 g. The sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 J/(g • °C). How much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°C?

Use mc018-1.jpg.
7.85 kJ
10.6 kJ
22.5 kJ
47.9 kJ

User Kathandrax
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7.6k points

2 Answers

5 votes

Answer:

22.5kJ

Step-by-step explanation:

your welcome

User Jon Hudson
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8.3k points
5 votes
The correct response is 22.5kJ of energy released by the reaction.

In this problem, we simply apply the specific heat equation which is:
Heat added = specific heat x mass x change in temperature

It is important to note that only the mass of the calorimeter is important, and masses should all be in grams, energy units are in joules.

mass calorimeter = 1350 g
change in temp = 2.87C
specific heat (calorimeter) = 5.82 J/g.C

heat added = 5.82 X 1350 x 2.87 = 22,549 Joules (J)
divide by 1000 to convert to kilojoules, = 22.5kJ

User Yudit
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8.1k points