Question

What is the solution of the equation when solved over the complex numbers?

x^2+24=0
x =
or x =

Answer 1

`{x}^(2) + 24 = 0 \\ (x - √(24))(x + √(24) ) = 0 \\ (x - √(4) √(6))(x + √(4) √(6)) = 0`

`(x - 2 √(6))(x + 2 √(6) ) = 0 \\ so \: x = 2 √(6) = 4.899 \: and \\ x = - 2 √(6) = - 4.899`