Question

Use a quadratic equation to find two real numbers that satisfies the situation. The sum of the two numbers is 2, and their product is –48.

Answer 1

To find two real numbers whose sum is 2 and product is -48, we form a quadratic equation x^2 - 2x - 48 = 0. Using the quadratic formula, we get two pairs of numbers (8, -6) and (-6, 8) that satisfy the given conditions.

Step-by-step explanation:

To find two real numbers that satisfy the given conditions, namely their sum being 2 and their product being –48, we can set up a system of equations or use a . Let's denote the two numbers as x and y. We know:

• x + y = 2
• xy = -48

We can express y in terms of x from the first equation: y = 2 - x. Substituting this into the second equation gives us:

x(2 - x) = -48

This simplifies to a quadratic equation:

x^2 - 2x - 48 = 0

Using the, x = (-b ± √(b^2 - 4ac)) / (2a), with a = 1, b = -2, and c = -48, we find the two possible values for x, which in turn gives us the corresponding values for y:

x = (2 ± √(4 + 192)) / 2

x = (2 ± √196) / 2

x = (2 ± 14) / 2

Therefore, the two solutions are x = 8 or x = -6. Since we were looking for two numbers, using x + y = 2, the corresponding y values are y = -6 and y = 8, respectively. Hence, the two pairs of numbers that satisfy the conditions are (8, -6) and (-6, 8).

Answer 2

a+b=2 and ab=-48, let a=x and y=b
x+y=2 implies y=2-x
xy=-48 implies x(2-x)=-48
so 2x-x^2+48=0