Question

Describe the vertical asymptote and hole for the graph of

Answer 1

We will have the following:

`y=(x-5)/((x+3)(x+1))`

From this, we have that the graph will have vertical asymptotes when:

`x^2+4x+3=0\Rightarrow(x+3)(x+1)=0`

So, it will have asymptotes at x = -3 and x = -1.

We will also have that the expression has no holes.