Answer:
Follows are the solution to the given question:
Step-by-step explanation:
The rectangular part has a length of
and its rectangular part has a width of
.
In option A
Calculating the area of the rectangular throgh the given piece:
![\to A_R = WL=(14 mm) (4.98 mm) =69.72 \ mm^2](https://img.qammunity.org/2022/formulas/physics/college/l9qi4t74fev70lfgpadd51ptv1d8mpba6u.png)
In option B
Calculating the ratio of rectangle's width which is rectangle's length:
![\to R_(WL)=(W)/(L)= (4.98 \ mm)/(14 \ mm) = 0.3557](https://img.qammunity.org/2022/formulas/physics/college/5fler949i5qzkronqqhtnwcnlynzriu2zt.png)
So, the ratio of rectangle's width to rectangle's length is 0.3557 .
In option C
Calculating the Perimeter of the rectangle:
In option D
Calculating the difference between length and width:
![\to D_(LW) = L- W = 14\ mm -4.98 \ mm =9.02 \ mm](https://img.qammunity.org/2022/formulas/physics/college/f5h85fis558ds8n56ctly7d8tj92q9ua0d.png)
In option E
Calculating the ratio of length to width: