Step-by-step explanation:
The specific heat of fusion of water is the amount of heat that 1 g of ice at 0 °C must absorb to become 1 g of liquid water at 0 °C. It's the same amount of heat that me must remove (with different sign) from 1 g of liquid water at 0°C to convert it to 1 g of ice at 0 °C.
Speficif heat of fusion = 0.334 kJ/g
So to freeze 1 g of liquid water at 0 °C we must remove 0.334 kJ, let's find the amount of heat that we must remove from 1.50 * 10^2 g of water.
Q = - Cf * mass
Q = -0.334 kJ/g * 1.50 * 10^2 g
Q = -50.1 kJ
Answer: -50.1 kJ must be removed.