Question

Which equivalence factor set should you use to convert 126 g c to atoms c? (1 mol c/126 g c)(6.02 x 1023 atoms c/1 mol

c.(1 mol c/12.01 g c)(6.02 x 1023 atoms c/1 mol
c.(12.01 g c/1 mol c)(1 mol c/6.02 x 1023 atoms
c.(12.01 g c/1 mol c)(6.02 x 1023 atoms c/1 mol c)?

Answer 1

For this you must Cross multiply and cancel any two units that are the same and diagonal from each other.

I attached a screenshot of my work. Hopefully it all makes sense.

Answer 2

Answer: The equivalence factor set that should be used is
`(126g)/(12.01g)* 6.022* 10^(23)`

Step-by-step explanation:

Molar mass of a substance is defined as the mass of one mole of a substance.

We know that:

Molar mass of carbon atom = 12.01 g/mol

Given mass of carbon atom = 126 grams

Applying unitary method:

12.01 grams of carbon occupies 1 mole

So, 126 grams of carbon will occupy =
`(1mol)/(12.01g)* 126g`

According to mole concept:

1 mole of an element contains
`6.022* 10^(23)` number of atoms

So,
`(1mol)/(12.01g)* 126g` of carbon will contain =
`(1mol)/(12.01g)* 126g* (6.022* 10^(23))/(1mol)=(126g)/(12.01g)* 6.022* 10^(23)` number of atoms

Hence, the equivalence factor set that should be used is
`(126g)/(12.01g)* 6.022* 10^(23)`