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28 votes
Find the slope and y-intercept of the line and graph.y = -x + 2

User MusashiXXX
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1 Answer

24 votes
24 votes

Given the equation:


\text{ y = -x + 2}

The equation is already in the slope-intercept form, y = mx +b.

Where,

m = Slope of the line

b = Y-intercept

Thus,

The slope of the line, m = -1

The y-intercept = 2

In making the graph of the equation, we must determine at least two points of the line.

Let's determine two conditions: when x = 0 and y = 0.

Point 1: At x = 0,

y = -x + 2

y = 0 + 2

y = 2

(0,2)

Point 2: At y = 0,

y = -x + 2

0 = -x + 2

x = 2

(2,0)

The graph of the equation will be,

Find the slope and y-intercept of the line and graph.y = -x + 2-example-1
User Ragoczy
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3.1k points