Question

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Answer 1

the trick here is to substitute points given

`f(x) = a * {b}^(x)`
substituting point A x-value =b

`f(b) = a * {b}^(b)`
turns out false since (b,a*b^b) !=(b,0)
substituting point B x-value=0

`f(0) = a * {b}^(0) = a`
turns out true since (0,a)=(0,a)

we already got f(x) at x =0 which is not the point (0,0)
so c is false
substituting D x-value=a

`f(a) = a * {b}^(a)`

hence B is the correct answers