Answer:
Option B,
%
Step-by-step explanation:
The heterozygous genotype of the parent is Xx
The punnet square for the cross between the two parents having Xx genotype is
X x
X XX Xx
x Xx xx
Thus,
A represents the genotype – XX
B represents the genotype – Xx
C represents the genotype – Xx
D represents the genotype – xx
Out of four possible genotypes, XX (A) appears only once.
Thus the probability of occurrence of genotype A (XX) will be
%