Question

Can you please help me solve X in ln(2x+4).

Answer 1

Step 1:

Steps

Step a: Find some points on the exponential f(x). The more points we plot the better the graph will look.

Step b: Switch the x and y values to obtain points on the inverse.

Step c: Determine the asymptote.

`\begin{gathered} When\text{ y = 0} \\ y\text{ = ln(2x + 4)} \\ 0\text{ = ln(2x + 4)} \\ e^0\text{ = 2x = 4} \\ \text{1 = 2x + 4} \\ 2x\text{ = 1- 4} \\ 2x\text{ = -3} \\ x\text{ = }(-3)/(2)\text{ = -1.5} \end{gathered}`
`\begin{gathered} \text{when x = 0} \\ y\text{ = ln(2(0) + 4)} \\ y\text{ = ln(4)} \\ y\text{ = }1.39 \end{gathered}`

Step 2: