Question

Consider an airplane flying at a pressure altitude of 31500 ft and a density altitude of 28000 ft. calculate the outside air temperature. (round the final answer to the nearest whole number.)

Answer 1

1° C

Step-by-step explanation:

Thinking process:

The expression for the temperature of air in terms of the density is given as follows:

T =
`(P )/(\rho R )`

where
`\rho` is the density of air

P is the pressure of the air

R is the characteristic gas constant

pressure of air at 31500 ft ≈ 23 800 Pa

Thus:

T =
`(23.800Pa)/(1.225* 287.05)`

= 1°