Question

A line passes through the points (–1, –5) and (4, 5). The point (a, 1) is also on the line.

Answer 1

y+5= -3 (x-1); y = -3x -2 (grad point)

Explanation:

Answer 2

Find the equation of the line through the points (–1, –5) and (4, 5). First, find the slope: m = rise / run = 5/10 = 1/2.

Then the equation is y-5=(1/2)(x-4). If (a,1) is on this line, (a,1) must satisfy the given equation. Let y=1 and solve for x:

1-5 = (1/2)(x-4) Mult both sides by 2 to get -2 = x-4. Then x = -4+2 = -2

So (-2,1) is also on the line.