Question

Please help I am confused.

Answer 1

y = 15° , ∠BAC = 78° , ∠ABC = 68° , ∠ACB = 34°

Explanation:

we can find ∠ACB as it lies on a straight line,

∠ACB + 146 = 180°

∠ACB = 180° - 146°

∠ACB = 34°

We know that all sides of triangle equals to 180°

so,

∠BAC + ∠ABC + ∠ACB = 180°

5y + 3 + 4y + 8 + 34 = 180°

9y + 45° = 180°

9y = 135°

y = 15°

So know we can find angles =

∠BAC = 5y + 3 = 5(15) + 3 = 78°

∠ABC = 4y + 8 = 4(15) + 8 = 68°

we already know that ∠ACB = 34°