Question

A wooden block has a mass of 20.0 kg and a specific heat of 1700 J/kg °C. Find the change in thermal energy of the block as it warms from 15.0°C to 25.0°C.

Answer 1

The change in thermal energy of a wooden block with a mass of 20.0 kg and a specific heat of 1700 J/kg°C warming from 15.0°C to 25.0°C is 340,000 Joules (or 340 kJ).

Step-by-step explanation:

To find the change in thermal energy of the block as it warms from 15.0°C to 25.0°C, we can use the formula for specific heat capacity, which is Q = mcΔT. Here, Q represents the thermal energy transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

For the given wooden block, we know:

• Mass (m) = 20.0 kg
• Specific heat (c) = 1700 J/kg°C
• Initial temperature (T1) = 15.0°C
• Final temperature (T2) = 25.0°C
• Change in temperature (ΔT) = T2 - T1 = 25.0°C - 15.0°C = 10.0°C

Now we can calculate the change in thermal energy:

Q = mcΔT = (20.0 kg)(1700 J/kg°C)(10.0°C) = 340,000 J

Therefore, the change in thermal energy of the wooden block is 340,000 Joules (or 340 kJ).

Answer 2

m = 20.0kg, the mass of the block.
c = 1700 J/(kg-°C), the specific heat
ΔT = 25 - 15 = 10 °C = 10 K, the change in temperature.

The change in thermal energy is

`Q = (20.0 \, kg)*(1700 \, (J)/(kg-C) )*(10 \, C) = 340 * 10^(3) \, J`

Answer: 340 kJ (or 340,000 J)