Question

Y=-5/4x-4 into standard form

Answer 1

Two of the forms of the equation of the line are:

`\begin{gathered} y=mx+b\Rightarrow\text{ Slope-intercept form} \\ ax+by=c\Rightarrow\text{ Standard form } \end{gathered}`

To take the equation of the line from its slope-intercept form to its standard form, just solve for the constant:

`\begin{gathered} y=-(5)/(4)x-4 \\ \text{ Multiply by 4 from both sides of the equation} \\ 4y=4\cdot(-(5)/(4)x-4) \\ 4y=-5x-16 \\ \text{ Add 5x from both sides of the equation} \\ 4y+5x=-5x-16+5x \\ 4y+5x=-16 \\ \text{ Reorder} \\ 5x+4y=-16 \end{gathered}`

Therefore, the equation of the line in its standard form is

`5x+4y=-16`