Question

Which equation represents a line that passes through (–9, –3) and has a slope of –6?

Answer 1

D).y+3=-6(x+9)

Explanation:

took it on edge

Answer 2

The required equation of line is y=-6x-57.

Explanation:

The point slope form of a line is

`y-y_1=m(x-x_1)`

Where m is slope of the line.

It is given that a line that passes through (–9, –3) and has a slope of –6.

Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.

`y-(-3)=-6(x-(-9))`

`y+3=-6x-54`

Subtract 3 from both the sides.

`y=-6x-54-3`

`y=-6x-57`

Therefore the required equation of line is y=-6x-57.