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1. Assume it takes 7.00 min to fill a 30.0-gal gasoline tank. a. calculate the rate at which the tank is filled in gallons per second? b. calculate the rate at which the tank is filled in cubic meters per second? C. determine the time interval, in hours, required to fill a 1.00-m3 volume at the same rate. (1 U.S. gal=231in.3)

User Finki
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2 Answers

4 votes

Final answer:

a. The rate at which the tank is filled is 16.5 gallons per second. b. The rate at which the tank is filled is 0.0273 cubic meters per second. c. It would take approximately 36.6 seconds to fill a 1.00 m³ volume at the same rate.

Step-by-step explanation:

a. To calculate the rate at which the tank is filled in gallons per second, we need to convert the time from minutes to seconds and divide the volume of the tank by the time taken to fill it.
1 gallon = 231 cubic inches

30 gallons = 30 x 231 cubic inches = 6930 cubic inches

Rate = Volume / Time

= 6930 cubic inches / (7 minutes x 60 seconds/minute)

= 16.5 cubic inches/second

b. To calculate the rate at which the tank is filled in cubic meters per second, we need to convert the volume from gallons to cubic meters and divide it by the time taken to fill the tank.

1 cubic meter = 1000 liters
1 gallon = 3.785 liters
30 gallons = 30 x 3.785 liters = 113.55 liters
1 liter = 0.001 cubic meters
113.55 liters = 113.55 x 0.001 cubic meters = 0.11355 cubic meters
Rate = Volume / Time

= 0.11355 cubic meters / (7 minutes x 60 seconds/minute)

= 0.0273 cubic meters/second

c. To determine the time interval required to fill a 1.00-m³ volume at the same rate, we need to divide the volume by the rate.

Time = Volume / Rate

= 1.00 m³ / 0.0273 cubic meters/second

= 36.6 seconds

User Ela Buwa
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8.2k points
7 votes
a) 0.07142 gal/sec = 30/7/60

b) convert 30 gal to m³

30 gal= 0.11356 m³ apprx

rate= 0.11356/(7x60)=2.7 x 10^-4 m³ / sec

c)30 gal= 30x 231=6930 in^3

rate of filling 1 in³ = 6930/(7x60)=16.5 in³ /sec

User Audrey Dutcher
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