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A sequence consists of 16 consecutive even integers written in increasing order. the sum of the first 8 of these even integers is 424. what is the sum of the last 8 of the even integers?
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A sequence consists of 16 consecutive even integers written in increasing order. the sum of the first 8 of these even integers is 424. what is the sum of the last 8 of the even integers?

User Bilelovitch
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using a formula x+(x+2)±(x+4)..., I found that the first integer, x, is 46. Now, I just work out the rest, which is 8x+16+18+20+22+24+26+28+30, or 800
User Estelle
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