Question

You throw a ball straight up into the air at a speed of 15 m/s.  You want to know how high above your hand the ball will be at exactly 2.5 sec after you released it.

Answer 1

Velocity initial would equal 15 m/s
Acceleration would be -9.81 m/s^2 (vertically fired object)
Time = 2.5 s

Use the equation d=vit+1/2at^2

d = 15(2.5) + 1/2(-9.81)(2.5)^2

d= 6.8 or 7 meters