Question

Solve this quadratic equation using the quadratic formula. (3 - y)(y + 4) = 3y - 5

Answer 1

y=(4 plus or minus 2√21

Explanation:

Answer 2

-y^2-4y+3y+12=3y-5
-y^2-4y+17=0
b^2-4ac=(-4)^2-4*(-1)*17=16+68=84
y=(4 plus or minus 2√21)/(-2)= -2 plus or minus √21