Question

A car increases its speed from 9.6 meters per second to 11.2 meters per second in 4.0 seconds. The average acceleration of the car during this 4.0-second interval is

Answer 1

The acceleration is the change of speed/velocity over time. Thus to calculate this you do (V1-V2)/T or (11.2-9.6)/4 or 0.4 m/s^2

Answer 2

a=(vf-vi)/t
a=(11.2-9.6)/4
a=0.4m/s^2