Question

Suppose a problem has vertex (5 -3) and also passes through the point (6,1) write the equation of the parabola in vertex form.

A) y= (x-5)^2-3
B) y= 4(x-5)^2-3
C) y=4(x+5)^2-3
D) y=4(x-5)^2+3

Answer 1

In vertex form it s
y = a(x - 5)^2 - 3 because the vertex is at (5,-3) . a is a constant to be found.
Plugging in the point (6,1) we get

1 = a(6-5)^2 - 3
1 = a - 3
a = 4

answer is y = 4(x - 5)^2 - 3

Its B