104k views
3 votes
Calculate all four second-order partial derivatives of f(x,y)=sin(2xy)

User GKP
by
7.7k points

1 Answer

7 votes
z = sin(2xy) Ill use D for the partial differential sign

Dz/Dx = 2ycos(2xy)
Dz/Dy = 2xcos(2xy)

D^2z/Dx^2 = 2y.-2ysin(2xy) = - 4y^2sin(2xy)
D^2z/Dy^2 = -4x^2sin(2xy)

D^2z/Dy.Dx = D/Dy( Dz/Dx) = 2y. -2xsin(2xy) + 2.cos(2xy)

= -4xysin(2xy) + 2 cos(2xy)

D^2z(Dx.Dy) is the same as the latter.
User Bane
by
7.6k points