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What is the coefficient of x7 in the expansion of (1 + x)11?

User Tough
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You can choose to expand the equation to find the coefficient of x7 but that would take a lot of time. Here is a useful tactic that can help;

11C(something)(1)(x)⁷ ----> This gives the coefficient of x⁷
11C7(1)⁴(x)⁷ ----> You know that pascal's triangle is equal on both sides
11C7×1⁴ = coefficient of x⁷ (just ignore x⁷)
330x1⁴=330

This means that the coefficient of x⁷ is 330. You can double check by expanding the equation. If you do not understand what I did there, you can ask me how I got to the solution.

Hope I helped :)
User Metasoarous
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