The given in this problem are:
99% confidence level
N = 61
Mean = 2.0 kg
Standard deviation = 4.8
Z value for a 9% confidence interval is 2.576
Confidence Interval = mean ± Z s/ sqrt n
= 2.0 ± 2.576(4.8/sqrt 61)
=2.0 ± 2.576 (0.6145770236779006736364371988794)
= 2.0 ± 1.5832
= 0.4168 < x < 3.5832