Question

A line has a slope of mc013-1.jpg and passes through the point (–5, 4). Which is the equation of the line?

Answer 1

y - 4= 3/4(x + 5)

y - 4= - (3/4)x - 15/4

y - 16/4= -(3/4)x - 15/4

y= - (3/4)x + 1/4

the answer is b

Answer 2

y =
`(-3x)/(4)` +
`(1)/(4)`.

Explanation:

Given : Graph of slope
`(-3)/(4)` and passes through the point (–5, 4).

To find : Which is the equation of the line.

Solution : we have given that point ( -5 ,4)

By equation of line (
`y-y_(1)) = m (x -x_(1))`

y - 4 =
`(-3)/(4)`( x +5).

y - 4 =
`(-3x)/(4)` +
`(-15)/(4)`.

On adding 4 both sides we get,

y =
`(-3x)/(4)` +
`(-15)/(4)+4`.

y =
`(-3x)/(4)` +
`(-15 +16)/(4)`.

y =
`(-3x)/(4)` +
`(1)/(4)`.

Therefore, y =
`(-3x)/(4)` +
`(1)/(4)`.