Question

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Answer 1

Given the set of equations:

x + y = 2

3x - 2y = 6

Let's solve the set of equations simultaneously using substitution method.

x + y = 2................................eqaution 1

3x - 2y = 6............................equation 2

Rewrite equation 1 for y:

x = 2 - y

Substitute (2 - y) for x in equation 2:

3x - 2y = 6

3(2 - y) - 2y = 6

Apply distributive property:

3(2) - 3(y) - 2y = 6

6 - 3y - 2y = 6

6 - 5y = 6

Subtract 6 from both sides:

6 - 6 - 5y = 6 - 6

-5y = 0

Divide both sides by -5:

`\begin{gathered} (-5y)/(-5)=(0)/(-5) \\ \\ y=0 \end{gathered}`

Substitute 0 for y in either of the equations to find x.

Let's take equation 1.

x + y = 2

x + 0 = 2

x = 2

Therefore, the value of x is 2 and the value of y is 0

x = 2, y = 0

ANSWER:

x = 2, y = 0