Question

Ballon volume of 3200ml of xenon gas is at a gauge pressure of 122kPa and a temperature of 27c. What is the volume when the balloon is heated to 65c and Guage pressure decreased to 112 kpa?

Answer 1

Given:

The initial volume of the gas, V₁=3200 ml=3.2×10⁻³ m³

The initial pressure of the gas, P₁=122 kPa

The initial temperature of the gas, T₁=27 °C=300 K

The final temperature, T₂=65 °C=338 K

The final pressure, P₂=112 kPa

To find:

The final volume of xenon gas.

Step-by-step explanation:

From the combined gas law,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

Where V₂ is the volume after it is heated.

On rearranging the above equation,

`V_2=(T_2P_1V_1)/(T_1P_2)`

On substituting the known values,

`\begin{gathered} V_2=(338*112*10^3*3.2*10^(-3))/(300*112*10^3) \\ =3.61\text{ m}^3 \end{gathered}`

Final answer:

The volume of the balloon when it is heated is 3.61 m³