To start this doozy of a problem, let's first get all the units in terms of meters and seconds, so that our problem is nice and easy to work with.
1km/hour = 1,000 meters/ 3600 seconds = .2777m/s
The plane's coming in at 300 *.277 = 83.33 m/s
The plane is coming in hot at 83.33m/s. How long will it take to come to a complete stop, given deceleration of -5m/s?
Vf = Vi + at ,
where Vf = final velocity, Vi=intiital velocty, a=acceleration, and t equals time. Let's solve for t. We plug 0 in for Vf, since final velocity will be zero (plane's not moving)
0 = 83.33 + (-5)t Subtract 83.33 from both sides
-83.33 = -5t Divide both sides by 5
t = 16.66
The plane needs 16.66 seconds to come to a stop. Is this enough time to avoid a fiery demise?
We have 500 m of runway to work with. To see if we have enough space to land, let's see how far we've traveled before we come to a complete stop, meaning how far we've traveled after 16.66 seconds.
d = vi(t) + (1/2) *a *t² where Vi= initial velocity. Let's solve for d
d = 83.33*16.66 + (1/2)(-5)(16.66²)
d = 1388.88 + (-2.5) (277.77)
d = 1388.88 - 694.44
d= 694.44
Looks like this pilot's out of luck, because he needs 194.44 meters more runway in order to survive this landing.