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When 250 grams of potassium hydroxide are dissolved in 2500 mls of water. The resulting volume is 2.585 liters of solution. What is the molarity of the solution?

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Since the molar mass of KOH is 56.105 g, you have 250/56.105 = 4.456 moles of KOH in 2.585 litres of solution, so the molarity is 4.456/2.585 = 1.724 M.

If you calculate the number of moles in 2500 mL of water and assume that the density of the solvent, water, is 1 kg/litre you obtain the molality m = 1.782 mol/kg
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